Setting Preflow. Does the math look right???
Posted: Sun Mar 27, 2016 7:36 pm
So, I've been wondering how to figure out, how much preflow is necessary to purge the total distance my lines run from flowmeter to torch, without using more preflow than necessary. Then I got to thinking what does the math say? I used the equation for finding the volume of a cylinder: pi x r^2 x h
The rough total distance my lines run from flowmeter to torch is around 37' feet, and the inner diameter of the hose is 3/16" of an inch.
First, I needed to convert the hose i.d. from inches to feet.
0.1875 / 12 = 0.015625
Then, I had to find the radius of a 3/16" of an inch hose.
0.015625 x 0.5 = 0.0078125
Solving the equation, the cubic feet of a 3/16" of an inch hose 37' feet in length is 0.0071.
3.1415926535897932384626433832795 x 0.0078125^2 x 37 = 0.0070946611439710906874461551014
Since there are 3,600 seconds in a hour; at a flowrate of 15 cfh every second will flow 0.0042 cubic feet. This is not accounting for any friction or restrictions in the lines.
15 / 3,600 = 0.00416666666666666666666666666667
Two seconds of preflow will be sufficient enough to purge the total distance my lines run.
0.0042 cubic feet per second x 2 seconds = 0.0084 cubic feet
Is the math right? Am I even using the right equation in the first place to find what I would roughly need to purge my lines?
The rough total distance my lines run from flowmeter to torch is around 37' feet, and the inner diameter of the hose is 3/16" of an inch.
First, I needed to convert the hose i.d. from inches to feet.
0.1875 / 12 = 0.015625
Then, I had to find the radius of a 3/16" of an inch hose.
0.015625 x 0.5 = 0.0078125
Solving the equation, the cubic feet of a 3/16" of an inch hose 37' feet in length is 0.0071.
3.1415926535897932384626433832795 x 0.0078125^2 x 37 = 0.0070946611439710906874461551014
Since there are 3,600 seconds in a hour; at a flowrate of 15 cfh every second will flow 0.0042 cubic feet. This is not accounting for any friction or restrictions in the lines.
15 / 3,600 = 0.00416666666666666666666666666667
Two seconds of preflow will be sufficient enough to purge the total distance my lines run.
0.0042 cubic feet per second x 2 seconds = 0.0084 cubic feet
Is the math right? Am I even using the right equation in the first place to find what I would roughly need to purge my lines?